I am the smallest positive integer that leaves a remainder of 1 when divided by 2, a remainder of 2 when divided by 3, a remainder of 3 when divided by 4, and a remainder of 4 when divided by 5. What number am I?
59
In each case, the remainder is 1 less than the divisor. This means adding 1 to the number makes it an exact multiple of 2, 3, 4, and 5. The least common multiple of 2, 3, 4, and 5 is 60. Subtracting 1 gives 59.
About this riddle
Math riddles hide a calculation inside a short story. Pull out the numbers, work out what is being asked, and watch for a trick such as a unit change.
Difficulty: Hard. More like this: Math riddles with answers or try Target 24 for a different kind of puzzle.
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