I am an odd number containing multiple digits. Take away my first digit, and I become an even number. What kind of number was I originally?

An odd number starting with an odd digit

If an odd number has its first digit removed and becomes even, the removed digit must have been odd (since odd minus odd is even, and changing the leading digit changes the parity depending on place value, wait: if the original number is odd, and removing the first digit makes it even, then the remaining part must have opposite parity if the place value shifted? Actually, if a number is odd, all its digits don't determine parity, only the last digit. Removing the *first* digit changes the place values of all remaining digits. If the remaining digits form an even number, it means the last digit must now be even. Therefore, the original number's last digit must have changed its effect on parity, which is impossible since the last digit didn't move. Wait, let's look at 38: 38 is even. 39: odd, remove 3 -> 9 (odd). 74: even. 76: even. Let's rethink: if you remove the first digit of 52 (even, remove 5 -> 2 even). If you remove the first digit of 56, you get 6. If you have an odd number like 34, remove 3 -> 4 (even). So the original number ended in an even digit, but was odd overall because of the first digit? No, the last digit determines parity. If the last digit is even, the whole number is even. So an odd number *cannot* end in an even digit. Thus, the riddle contains a trick or is flawed. Let's replace it with a valid one.