I am a positive integer. If you cube me and then subtract me from the result, the answer is a multiple of 6. Is this statement true for every positive integer, or only specific ones?
True for every positive integer
By algebraic factoring, n^3 - n = n(n-1)(n+1), which is the product of three consecutive integers. Among any three consecutive integers, at least one is even and one is a multiple of 3, meaning the product is always divisible by 6.
About this riddle
Math riddles hide a calculation inside a short story. Pull out the numbers, work out what is being asked, and watch for a trick such as a unit change.
Difficulty: Hard. More like this: Math riddles with answers or try Target 24 for a different kind of puzzle.
More math riddles
I am a two-digit number. My digits sum up to 10. If you multiply me by 3, the result is a number whose digits are the exact same as mine, just swapped. What number am I?
Kai counts chicks in a pattern: 2, 6, 10, 14. How many chicks come next?
A book has 300 pages. How many individual pages have a page number containing the digit 3 at least once?
Leo has 5 desks. Max has twice as many. How many desks do they have together?
I am a two-digit prime number. Reverse my digits and you get a perfect square. Add my digits together and you get another prime number. What number am I?
Pick any real number. Double it, add 14, divide the whole result by 2, and then subtract your starting number. What number will you always hold in your hand?

