A farmer has a basket of eggs. Counting them by 2s, 3s, 4s, 5s, or 6s always leaves 1 egg remaining. Counting them by 7s leaves zero eggs remaining. What is the smallest total number of eggs he could have?
301
The least common multiple of 2, 3, 4, 5, and 6 is 60. The total egg count must be of the form 60k + 1. Testing integer values for k shows that for k = 5, 60(5) + 1 = 301, which is divisible by 7 (301 ÷ 7 = 43).
About this riddle
Math riddles hide a calculation inside a short story. Pull out the numbers, work out what is being asked, and watch for a trick such as a unit change.
Difficulty: Medium. More like this: Math riddles with answers or try Target 24 for a different kind of puzzle.
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