Five identical boxes are lined up in a row. A prize is hidden in one of them. Box A says 'The prize is in Box B or C.' Box B says 'The prize is in an even-numbered box.' Box C says 'The prize is in Box A.' Box D says 'The prize is in Box E.' Box E says 'The prize is not in this box.' Only the box containing the prize is telling the truth; all other boxes contain false statements. Which box holds the prize?

Box D

Let's test each box. If D is true, then E is false (since the prize is in D, not E). This matches E's statement that the prize is not in E. A, B, and C would be false. Box A says prize is in B or C (false). Box B says prize is even (D is 4, which is even, wait, if D is 4, B would be true. Let's number them A=1, B=2, C=3, D=4, E=5). If D is the prize, Box B ('prize is in an even-numbered box') would be TRUE, which violates the rule that only ONE box tells the truth (if D and B are both true, that's two). Let's re-evaluate: Box E says 'The prize is not in this box.' If E is true, then E is NOT the prize. But if E is the only true box, who has the prize? Let's check Box B: 'The prize is in an even-numbered box' (2 or 4). If B is true, B contains the prize. But then B is telling the truth, and no other is true. Let's check B as the answer: If prize is in B (2, even), then B is true. Box A ('prize in B or C') is true. That's two truths. Let's check Box E: If prize is in E (5), then E says 'The prize is not in this box' which is false. Box D says 'The prize is in E' which is TRUE. Box B says 'even' (5 is odd, false). Box C says 'prize in A' (false). Box A says 'B or C' (false). So if E has the prize, ONLY D tells the truth. Let's double check D: if prize is in E, Box D is true. But wait, Box D says 'The prize is in Box E.' So D is true. And E says 'The prize is not in this box' which is FALSE because the prize IS in E. Thus, only D is telling the truth. Wait, does Box D contain the prize? No, D says the prize is in E. So E contains the prize, and D is the only truthful box.